Click the appropriate answer:

1The point , ---- is on the line Y=X-3

(2,3)
(1,-2)
(1,4)

2 For the line 2X-Y=5 if X=4 then Y =

8
13
3

3 The solution to 3X+2Y=-25, -2X-Y=10 is

(4,5)
(20,5)
(5,-20)

4 The point (0,5) is on

X axis
Y axis

5 If point (3,2) lies on a line || to Y axis, then equation of the line

y =2
X =3
X +Y =3

6 2X +3Y -5 = 0 and KX-6Y-8 =0 have unique solutions if K=

4
- 4
8

7 4X+Y =3, 8X+2Y=5X have infinite numberof solution if K

2/3
6/5
3/2

8 The value of K for equations 2X-Y+8=0, 4X-KY+16=0 to represent coincident lines is

2
4
3

9 If there is no solution for2X+KY=11,5X-7Y=5 then K=

14/15
-15/16
-14/15

10 The equations 4X+6Y=11, 2X+KY=7 are inconsistant if K=

4
3
7

11 If a numerator of a fraction multiplied by 3 and denominator is reduced by 3 we get 18/11 but if the numerator increased by 8 and denominator is doubled we get 2/5. Then the fraction is

13/25
20/21
12/25

12 A number consists of two digits, the sum of the digits being 10. If 18 is subtracted from the even number the digits are reversed. The number is

73
64
82

13 If 1 is added to the denominator to a certain fraction it becomes 1/3 and if 1 is subtracted from denominator it becomes 1/2, then the fraction is

2/5
3/8
4/9

14 A two digit no is six times the sum of its digits. The number obtained by interchanging the digit is less by 9, then the original number so the given number is

63
54
92

15 The sum of two integers is 88.If greater no is divided by the smaller, quotient is 5 & the reminder is 10 then the integers are (22,66)
(13,75)

(13,22)

16 If 2X-3y+5=0, 8x-KY+20=0 represent coinsident lines. Then K=

14
15
16

17 2X+KY=1, 5X-7Y=5 have no solution if K=

7/5
1/5
-14/15

18 If sum of digits of two digit no. is 9 and the digits obtained by interchanging the digits exceeds the given number by 27 then the number is

63
54
36

19 In a cyclic quadrilateral ABCD Ð A= (2X+y)o , ÐB=(y+3)o, Ð C=(2y+10)o , and ÐD=(4X-5)o, then ÐA=

90o
70o
100o

20 2X+Y-3=0, 2X-3Y-7=0 has point of intersection

(3,2)
(2,-1)
(4,3)

21 In the equation 2x-y=5 if X=4 then Y=

5
6
3

22 X/a+Y/b=2 ax-by =a2-b2 then x= &y=

(a and a)
(b and b)
(a and b)

23 x-y/3 = y+2/7, X = 3y+1/2 then X= & Y=

7 & 6
8 &5
5 & 3

24 If 5x+7y=3, 15X+21Y=K represent coincidet line then K=

10
9
8

25 Cost of 10 oranges and 12 mangoes is Rs 28, but cost of 12 oranges and 10 mangoes is Re. 1 less the cost of 2 oranges and 4 mangoes =

Rs 10
Rs 8
Rs 6

26 Point= ----- is on 3X+2y=1

6,-2
7,3

27 If 6a³b, 12a²b² and 48ab³ are in proportion then the value of K=

72a²b³
96a³b
24a²b²

28 7/x+13/Y= 27, 13/x+7/4= 33 then X= & y=

(1 & 2)
(1/2 & 1)
(3 & 4)

29 41m-47n=35, 47m-41n=53 then m= & n=

(3 & 4)
(4 & 5)
(2 & 1)

30 m-2/15 + n+2/12 = 5, m-2/12 + n+2/15 = 49/10 then m= & n=

(32 , 34)
(35 & 36)

31 x+4= 4, 2x-5y=1 then x= & y=

(4 & 5)
(1 &2)
(3 & 1)

32 x+1/8 = 4+3/5 =x-y/4 then x= & y=

(15 & 7)
(7 & 11)

33 Two persons a&b could finish a work in P days. They work together for q days. Then A left. The remaining work was done by B in r days A could do the same work in

pr /r+q-p
q / r+p-q

34 The line X=y passes through

origin
2,3
3,4